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Aldol Condensation Mechanism of Acetaldehyde

Step-by-step mechanism of aldol condensation for acetaldehyde, detailing enolate formation, nucleophilic addition, and dehydration to form an α,β-unsaturated aldehyde.

2 min readPublished 4 June 2026
Organic Chemistrynucleophilic additiondehydration to α-β unsaturated product

Concept Overview

This question tests the understanding of the aldol condensation reaction, a fundamental carbon-carbon bond-forming reaction in organic chemistry. The mechanism involves the formation of an enolate ion, followed by a nucleophilic attack on a carbonyl carbon, and finally dehydration to yield an α,β-unsaturated carbonyl compound. We will illustrate this with the specific example of acetaldehyde.

Step 1: Enolate Formation The reaction begins with a base (commonly hydroxide ion, OHOH^-) abstracting an acidic α-hydrogen from one molecule of acetaldehyde. This generates a resonance-stabilized enolate ion.

CH3CHO+OH[CH2CHO]+H2OCH_3CHO + OH^- \rightleftharpoons [CH_2CHO]^- + H_2O

The α-hydrogen is acidic due to the electron-withdrawing effect of the carbonyl group and the resonance stabilization of the resulting carbanion.

Step 2: Nucleophilic Attack The enolate ion, acting as a nucleophile, attacks the electrophilic carbonyl carbon of a second acetaldehyde molecule. This forms an alkoxide intermediate.

[CH2CHO]+CH3CHOCH3CH(O)CH2CHO[CH_2CHO]^- + CH_3CHO \rightarrow CH_3CH(O^-)CH_2CHO

The negative charge on the enolate carbon attacks the partially positive carbonyl carbon, forming a new carbon-carbon bond.

Step 3: Protonation of the Alkoxide The alkoxide intermediate is then protonated by water (or another proton source) to form the β-hydroxy aldehyde, also known as the aldol adduct.

CH3CH(O)CH2CHO+H2OCH3CH(OH)CH2CHO+OHCH_3CH(O^-)CH_2CHO + H_2O \rightarrow CH_3CH(OH)CH_2CHO + OH^-

This step regenerates the hydroxide catalyst and yields the initial aldol product.

Step 4: Dehydration (Elimination) Under slightly acidic or basic conditions and often with heating, the β-hydroxy aldehyde undergoes dehydration to form an α,β-unsaturated aldehyde. The hydroxide ion (or acid) can catalyze this step. First, the α-hydrogen is removed to form an enolate.

CH3CH(OH)CH2CHO+OHCH3CH(OH)CHCHO+H2OCH_3CH(OH)CH_2CHO + OH^- \rightleftharpoons CH_3CH(OH)CH^-CHO + H_2O

Step 5: Elimination of Water The enolate then eliminates a hydroxide ion (or water molecule if acid-catalyzed) to form the conjugated α,β-unsaturated aldehyde.

CH3CH(OH)CHCHOCH3CH=CHCHO+OHCH_3CH(OH)CH^-CHO \rightarrow CH_3CH=CHCHO + OH^-

This dehydration step is driven by the formation of a stable conjugated system. The final product for acetaldehyde is but-2-enal, commonly known as crotonaldehyde.

Key Takeaways:

  • Aldol condensation involves the formation of a new carbon-carbon bond between two carbonyl compounds.
  • The mechanism proceeds via enolate formation, nucleophilic addition to a carbonyl, and dehydration.
  • Acetaldehyde, having α-hydrogens, can undergo self-condensation.
  • The final product is typically an α,β-unsaturated aldehyde or ketone.

Answer: The aldol condensation of acetaldehyde proceeds through enolate formation, nucleophilic attack on another acetaldehyde molecule, protonation to form 3-hydroxybutanal, and subsequent dehydration to yield but-2-enal (crotonaldehyde).

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